126 lines
		
	
	
		
			4.0 KiB
		
	
	
	
		
			Python
		
	
	
			
		
		
	
	
			126 lines
		
	
	
		
			4.0 KiB
		
	
	
	
		
			Python
		
	
	
###########################################################################
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# Copyright 2019 (C) Hui Lan <hui.lan@cantab.net>
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# Written permission must be obtained from the author for commercial uses.
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###########################################################################
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import collections
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import html
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import string
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import operator
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import os, sys # 引入模块sys,因为我要用里面的sys.argv列表中的信息来读取命令行参数。
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import pickle_idea
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def freq(fruit):
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    '''
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    功能: 把字符串转成列表。 目的是得到每个单词的频率。
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    输入: 字符串
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    输出: 列表, 列表里包含一组元组,每个元组包含单词与单词的频率。 比如 [('apple', 2), ('banana', 1)]
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    注意事项: 首先要把字符串转成小写。原因是。。。
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    '''
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    result = []
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    fruit = fruit.lower() # 字母转小写
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    flst = fruit.split()  # 字符串转成list
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    c = collections.Counter(flst)
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    result = c.most_common()
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    return result
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def youdao_link(s): # 有道链接
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    link = 'http://youdao.com/w/eng/' + s + '/#keyfrom=dict2.index'# 网址
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    return link
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def file2str(fname):#文件转字符
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    f = open(fname) #打开
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    s = f.read()    #读取
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    f.close()       #关闭
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    return s
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def remove_punctuation(s): # 这里是s是形参 (parameter)。函数被调用时才给s赋值。
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    special_characters = '\_©~<=>+/[]*&$%^@.,?!:;#()"“”—‘’{}|,。?!¥……()、《》:;·' # 把里面的字符都去掉
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    s = html.unescape(s) # 将HTML实体转换为对应的字符,比如<会被识别为小于号
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    for c in special_characters:
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        s = s.replace(c, ' ') # 防止出现把 apple,apple 移掉逗号后变成 appleapple 情况
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    s = s.replace('--', ' ')
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    s = s.strip() # 去除前后的空格
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    if '\'' in s:
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        n = len(s)
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        t = '' # 用来收集我需要保留的字符
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        for i in range(n): # 只有单引号前后都有英文字符,才保留
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            if s[i] == '\'':
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                i_is_ok = i - 1 >= 0 and i + 1 < n
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                if i_is_ok and s[i-1] in string.ascii_letters and s[i+1] in string.ascii_letters:
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                    t += s[i]
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            else:
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                t += s[i]
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        return t
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    else:
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        return s
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def sort_in_descending_order(lst):# 单词按频率降序排列
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    lst2 = sorted(lst, reverse=True, key=lambda x: (x[1], x[0]))
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    return lst2
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def sort_in_ascending_order(lst):# 单词按频率降序排列
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    lst2 = sorted(lst, reverse=False, key=lambda x: (x[1], x[0]))
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    return lst2
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def make_html_page(lst, fname):  # 只是在wordfreqCMD.py中的main函数中调用,所以不做修改
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    '''
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    功能:把lst的信息存到fname中,以html格式。
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    '''
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    s = ''
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    count = 1
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    for x in lst:
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        # <a href="">word</a>
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        s += '<p>%d <a href="%s">%s</a> (%d)</p>' % (count, youdao_link(x[0]), x[0], x[1])
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        count += 1
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    f = open(fname, 'w')
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    f.write(s)
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    f.close()
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## main(程序入口)
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if __name__ == '__main__':
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    num = len(sys.argv)
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    if num == 1: # 从键盘读入字符串
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        s = input()
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    elif num == 2: # 从文件读入字符串
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        fname = sys.argv[1]
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        s = file2str(fname)
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    else:
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        print('I can accept at most 2 arguments.')
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        sys.exit()# 结束程序运行, 下面的代码不会被执行了。
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    s = remove_punctuation(s) # 这里是s是实参(argument),里面有值
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    L = freq(s)
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    for x in sort_in_descending_order(L):
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        print('%s\t%d\t%s' % (x[0], x[1], youdao_link(x[0])))#函数导出
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    # 把频率的结果放result.html中
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    make_html_page(sort_in_descending_order(L), 'result.html')
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    print('\nHistory:\n')
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    if os.path.exists('frequency.p'):
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        d = pickle_idea.load_record('frequency.p')
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    else:
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        d = {}
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    print(sort_in_descending_order(pickle_idea.dict2lst(d)))
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    # 合并频率
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    lst_history = pickle_idea.dict2lst(d)
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    d = pickle_idea.merge_frequency(L, lst_history)
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    pickle_idea.save_frequency_to_pickle(d, 'frequency.p')
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