59 lines
2.2 KiB
Python
59 lines
2.2 KiB
Python
from selenium import webdriver
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from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
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from selenium.webdriver.support import expected_conditions as EC
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from selenium import webdriver
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from selenium.webdriver.support.wait import WebDriverWait
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from selenium.webdriver.common.by import By
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from selenium.webdriver.common.keys import Keys
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import logging
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import time
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import pytest
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@pytest.mark.parametrize("test_input,expected",
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[("‘test1’", "test1"),
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("'test2'", "test2"),
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("“test3”", "test3"),
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("it's", "it's"),
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("hello,I'm linshan", ["hello","i'm","linshan"]),
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("Happy New Year！？", ["happy","new","year"]),
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("My favorite book is 《Harry Potter》。", ["potter","harry","my","favorite","book","is"])])
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def test_bug553_LinShan(test_input,expected, driver, URL):
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try:
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# 打开对应地址的网页
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driver.get(URL)
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# 浏览器最大窗口化
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driver.maximize_window()
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# 判断网页源代码中是否有English Pal -文字
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assert 'English Pal -' in driver.page_source
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# 将测试的数据输入到主页的textarea里
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driver.find_element_by_xpath("//textarea[@name='content']").send_keys(Keys.CONTROL, "a")
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driver.find_element_by_xpath("//textarea[@name='content']").send_keys(test_input)
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time.sleep(1)
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# 点击按钮获取单词
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driver.find_element_by_xpath("//input[@value='get文章中的词频']").click()
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time.sleep(1)
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# 获取筛选后的单词
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words = driver.find_elements_by_xpath("//p/a")
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# 遍历获取到的单词，并判断单词与预期的相同
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for word in words:
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# 判断单词是否在预期结果中
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assert word.text in expected
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# 返回上一页网页
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driver.find_element_by_xpath("//input[@value='确定并返回']").click()
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time.sleep(0.1)
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except Exception as e:
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# 输出异常信息
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logging.error(e)
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# 关闭浏览器
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driver.quit()
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finally:
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driver.quit()
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