70 lines
2.1 KiB
Python
70 lines
2.1 KiB
Python
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import random
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import string
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import time
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from selenium.webdriver.common.by import By
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from selenium.webdriver.support.ui import WebDriverWait
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from selenium.webdriver.support import expected_conditions as EC
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from selenium.webdriver.common.action_chains import ActionChains
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from helper import signup
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def has_punctuation(s):
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return any(c in string.punctuation for c in s)
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def select(driver):
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text_element = driver.find_element(By.ID, 'article')
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# 创建ActionChains对象
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actions = ActionChains(driver)
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# 模拟鼠标移动到文本元素上
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actions.move_to_element(text_element)
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# 模拟鼠标按下并拖动以选择文本
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# 假设我们想要选择从第10个字符开始的5个字符
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actions.click()
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actions.perform()
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time.sleep(5)
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# 找到包含要选择文字的元素
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text_element = driver.find_element(By.ID, 'article_title')
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# 创建ActionChains对象
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actions = ActionChains(driver)
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# 模拟鼠标移动到文本元素上
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actions.move_to_element(text_element)
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# 模拟鼠标按下并拖动以选择文本
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actions.double_click()
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actions.perform()
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actions.release() # 释放鼠标按钮
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def test_selected_second_word(driver, URL):
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try:
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username, password = signup(URL, driver)
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# 找到包含要选择文字的元素
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text_element = driver.find_element(By.ID, 'article_title')
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# 创建ActionChains对象
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actions = ActionChains(driver)
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# 模拟鼠标移动到文本元素上
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actions.move_to_element(text_element)
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# 模拟鼠标按下并拖动以选择文本
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actions.double_click()
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actions.perform()
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# 获取选中的文本
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selected_words = driver.find_element(By.ID, 'selected-words').get_attribute('value')
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assert selected_words != "","选中单词被放置框中"
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#再次选取
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select(driver)
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time.sleep(6)
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selected_second_words = driver.find_element(By.ID, 'selected-words').get_attribute('value')
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assert selected_second_words.strip() == "", "选中的单词被删除"
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finally:
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driver.quit()
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