121 lines
3.9 KiB
Python
121 lines
3.9 KiB
Python
###########################################################################
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# Copyright 2019 (C) Hui Lan <hui.lan@cantab.net>
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# Written permission must be obtained from the author for commercial uses.
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###########################################################################
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import collections
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import string
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import operator
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import os, sys # 引入模块sys，因为我要用里面的sys.argv列表中的信息来读取命令行参数。
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import pickle_idea
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def freq(s):
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'''
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功能： 把字符串转成列表。 目的是得到每个单词的频率。
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输入： 字符串
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输出： 列表， 列表里包含一组元组，每个元组包含单词与单词的频率。 比如 [('apple', 2), ('banana', 1)]
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注意事项： 首先要把字符串转成小写。原因是。。。
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'''
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result = []
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s = s.lower() # 字母转小写
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word_lst = s.split() # 字符串转成list
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c = collections.Counter(word_lst)
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result = c.most_common()
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return result
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def youdao_link(word): # 有道链接
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link = 'http://youdao.com/w/eng/' + word + '/#keyfrom=dict2.index' # 网址
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return link
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def file_to_str(f_name): # 文件转字符
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f = open(f_name) # 打开
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f_str = f.read() # 读取
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f.close() # 关闭
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return f_str
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def remove_punctuation(s): # 这里是words_text是形参 (parameter)。函数被调用时才给words_text赋值。
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special_characters = '\_©~<=>+-/[]*&$%^@.,?!:;#()"“”—‘’{}|' # 把里面的字符都去掉
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for c in special_characters:
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s = s.replace(c, ' ') # 防止出现把 apple,apple 移掉逗号后变成 appleapple 情况
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s = s.replace('--', ' ')
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s = s.strip() # 去除前后的空格
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if '\'' in s:
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n = len(s)
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characters = '' # 用来收集我需要保留的字符
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for i in range(n): # 只有单引号前后都有英文字符，才保留
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if s[i] == '\'':
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i_is_ok = i - 1 >= 0 and i + 1 < n
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if i_is_ok and s[i - 1] in string.ascii_letters and s[i + 1] in string.ascii_letters:
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characters += s[i]
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else:
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characters += s[i]
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return characters
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else:
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return s
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def sort_in_descending_order(lst): # 单词按频率降序排列
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lst2 = sorted(lst, reverse=True, key=lambda x: (x[1], x[0]))
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return lst2
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def sort_in_ascending_order(lst): # 单词按频率降序排列
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lst2 = sorted(lst, reverse=False, key=lambda x: (x[1], x[0]))
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return lst2
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def make_html_page(lst, fname): # 只是在wordfreqCMD.py中的main函数中调用，所以不做修改
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'''
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功能：把lst的信息存到fname中，以html格式。
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'''
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s = ''
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count = 1
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for x in lst:
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# <a href="">word</a>
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s += '<p>%d <a href="%s">%s</a> (%d)</p>' % (count, youdao_link(x[0]), x[0], x[1])
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count += 1
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f = open(fname, 'w')
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f.write(s)
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f.close()
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## main（程序入口）
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if __name__ == '__main__':
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num = len(sys.argv)
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if num == 1: # 从键盘读入字符串
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s = input()
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elif num == 2: # 从文件读入字符串
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fname = sys.argv[1]
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s = file_to_str(fname)
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else:
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print('I can accept at most 2 arguments.')
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sys.exit() # 结束程序运行， 下面的代码不会被执行了。
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s = remove_punctuation(s) # 这里是s是实参(argument)，里面有值
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L = freq(s)
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for x in sort_in_descending_order(L):
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print('%s\t%d\t%s' % (x[0], x[1], youdao_link(x[0]))) # 函数导出
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# 把频率的结果放result.html中
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make_html_page(sort_in_descending_order(L), 'result.html')
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print('\nHistory:\n')
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if os.path.exists('frequency.p'):
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d = pickle_idea.load_record('frequency.p')
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else:
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d = {}
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print(sort_in_descending_order(pickle_idea.dict_to_lst(d)))
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# 合并频率
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lst_history = pickle_idea.dict_to_lst(d)
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d = pickle_idea.merge_frequency(L, lst_history)
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pickle_idea.save_frequency_to_pickle(d, 'frequency.p')
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