bug修改,前面提交的first commit是重构

app/wordfreqCMD.py

@@ -38,20 +38,42 @@ def file2str(fname):#文件转字符
     return s
 
 
+def str2chararray(str):  # 字符串转字符数组
+    chararray = []
+    for i in range(len(str)):
+        chararray.append(str[i])
+    return chararray
+
+
 def remove_punctuation(s): # 这里是s是形参 (parameter)。函数被调用时才给s赋值。
-    special_characters = '_©~=+[]*&$%^@.,?!:;#()"“”—‘’' # 把里面的字符都去掉
+    # carr = str2chararray(s)  # 字符串转字符数组
+    # print(carr)
+    special_characters = '&_~=+[]%^@.,?!:;#()"“”—‘’|/\\<>{}'  # 把里面的字符都去掉
+    special_words = ('$lt', '$gt', '$')  # 特殊词汇
     for c in special_characters:
-        s = s.replace(c, ' ') # 防止出现把 apple,apple 移掉逗号后变成 appleapple 情况
+        s = s.replace(c, ' ')  # 防止出现把 apple,apple 移掉逗号后变成 appleapple 情况
+    carr = str2chararray(s)  # 字符串转字符数组
+    for i, value in enumerate(carr):
+        if value == '&':  # 遍历替换
+            carr[i] = '\''
+            print('sss' + s)
+            for j in range(1,5):
+                if carr[i+j] in [' ','3','9']:
+                    carr[i + j]=''
+    s = ''.join(carr)  # 字符数组转字符串
+    print('sss'+s)
+    for w in special_words:  # 替换字符串中的剩余特殊字符
+        s = s.replace(w, ' ')
     s = s.replace('--', ' ')
-    s = s.strip() # 去除前后的空格
-    
+    s = s.strip()  # 去除前后的空格
+
     if '\'' in s:
         n = len(s)
-        t = '' # 用来收集我需要保留的字符
-        for i in range(n): # 只有单引号前后都有英文字符，才保留
+        t = ''  # 用来收集我需要保留的字符
+        for i in range(n):  # 只有单引号前后都有英文字符，才保留
             if s[i] == '\'':
                 i_is_ok = i - 1 >= 0 and i + 1 < n
-                if i_is_ok and s[i-1] in string.ascii_letters and s[i+1] in string.ascii_letters:
+                if i_is_ok and s[i - 1] in string.ascii_letters and s[i + 1] in string.ascii_letters:
                     t += s[i]
             else:
                 t += s[i]
@@ -60,6 +82,7 @@ def remove_punctuation(s): # 这里是s是形参 (parameter)。函数被调用
         return s
 
 
+
 def sort_in_descending_order(lst):# 单词按频率降序排列
     lst2 = sorted(lst, reverse=True, key=lambda x: (x[1], x[0]))
     return lst2