为系统添加一个全局变量记录数据库的单词及其等级,使得数据库单词等级只需在登录时进行一次评级,大致能将点击下一篇的时间缩减为原来的10^-15次以下,感谢章翊、赵煜涵、唐伟、宋江涛同学的建议,没有他们我懒得改的
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@ -6,12 +6,14 @@
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# Purpose: compute difficulty level of a English text
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import pickle
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import math
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import time
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from wordfreqCMD import remove_punctuation, freq, sort_in_descending_order, sort_in_ascending_order
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import snowballstemmer
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from wordfreqCMD import remove_punctuation, freq, sort_in_descending_order, sort_in_ascending_order
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# 定义一个全局的res_d, 记录数据库单词评级之后的单词及其等级
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res_d = {}
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def load_record(pickle_fname):
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f = open(pickle_fname, 'rb')
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@ -43,7 +45,8 @@ def convert_test_type_to_difficulty_level(d):
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result[k] = 8
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time_end = time.time()
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print('convert_test_type_to_difficulty_level totally cost', time_end - time_start)
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global res_d
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res_d = result
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return result # {'apple': 4, ...}
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@ -55,7 +58,10 @@ def get_difficulty_level_for_user(d1, d2):
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"""
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time_start = time.time()
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# TODO: convert_test_type_to_difficulty_level() should not be called every time. Each word's difficulty level should be pre-computed.
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if res_d == {}:
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d2 = convert_test_type_to_difficulty_level(d2) # 根据d2的标记评级{'apple': 4, 'abandon': 4, ...}
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else:
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d2 = res_d
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stemmer = snowballstemmer.stemmer('english')
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for k in d1: # 用户的词
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