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bug修改,前面提交的first commit是重构

593
田其鹭 2023-04-27 16:00:46 +08:00
parent 61f46f7d58
commit 705aa5efcb
1 changed files with 30 additions and 7 deletions

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@ -38,10 +38,32 @@ def file2str(fname):#文件转字符
return s return s
def str2chararray(str): # 字符串转字符数组
chararray = []
for i in range(len(str)):
chararray.append(str[i])
return chararray
def remove_punctuation(s): # 这里是s是形参 (parameter)。函数被调用时才给s赋值。 def remove_punctuation(s): # 这里是s是形参 (parameter)。函数被调用时才给s赋值。
special_characters = '_©~=+[]*&$%^@.,?!:;#()"“”—‘’' # 把里面的字符都去掉 # carr = str2chararray(s) # 字符串转字符数组
# print(carr)
special_characters = '&_~=+[]%^@.,?!:;#()"“”—‘’|/\\<>{}' # 把里面的字符都去掉
special_words = ('$lt', '$gt', '$') # 特殊词汇
for c in special_characters: for c in special_characters:
s = s.replace(c, ' ') # 防止出现把 apple,apple 移掉逗号后变成 appleapple 情况 s = s.replace(c, ' ') # 防止出现把 apple,apple 移掉逗号后变成 appleapple 情况
carr = str2chararray(s) # 字符串转字符数组
for i, value in enumerate(carr):
if value == '&': # 遍历替换
carr[i] = '\''
print('sss' + s)
for j in range(1,5):
if carr[i+j] in [' ','3','9']:
carr[i + j]=''
s = ''.join(carr) # 字符数组转字符串
print('sss'+s)
for w in special_words: # 替换字符串中的剩余特殊字符
s = s.replace(w, ' ')
s = s.replace('--', ' ') s = s.replace('--', ' ')
s = s.strip() # 去除前后的空格 s = s.strip() # 去除前后的空格
@ -51,7 +73,7 @@ def remove_punctuation(s): # 这里是s是形参 (parameter)。函数被调用
for i in range(n): # 只有单引号前后都有英文字符,才保留 for i in range(n): # 只有单引号前后都有英文字符,才保留
if s[i] == '\'': if s[i] == '\'':
i_is_ok = i - 1 >= 0 and i + 1 < n i_is_ok = i - 1 >= 0 and i + 1 < n
if i_is_ok and s[i-1] in string.ascii_letters and s[i+1] in string.ascii_letters: if i_is_ok and s[i - 1] in string.ascii_letters and s[i + 1] in string.ascii_letters:
t += s[i] t += s[i]
else: else:
t += s[i] t += s[i]
@ -60,6 +82,7 @@ def remove_punctuation(s): # 这里是s是形参 (parameter)。函数被调用
return s return s
def sort_in_descending_order(lst):# 单词按频率降序排列 def sort_in_descending_order(lst):# 单词按频率降序排列
lst2 = sorted(lst, reverse=True, key=lambda x: (x[1], x[0])) lst2 = sorted(lst, reverse=True, key=lambda x: (x[1], x[0]))
return lst2 return lst2